Solve for x:4cos6x-sin6x=cos^3x+3cos2x
Solve for x:
4cos6x-sin6x=cos^3x+3cos2x
Gaurav , 10 Years ago
Grade
Trigonometry> Solve for x: 4cos6x-sin6x=cos^3x+3cos2x...
1 Answers
Sher Mohammad
Last Activity: 10 Years ago
4cos6x-sin6x=cos^3x+3cos2x
for x=0,.
4-0=1+3
means x=0 is a solution
for x=pi
4- 0= -1 +3 , not a solution.
hence only 2npi , is solution of the equation where n=1,2,3..............
Provide a better Answer & Earn Cool Goodies
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Other Related Questions on trigonometry
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available
Last Activity: 2 Years ago
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
- Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
0 Answer Available
Last Activity: 3 Years ago
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
0 Answer Available
Last Activity: 3 Years ago
cos^2 13ºcos^2 47º+cos^2 73º =? …..................
cos^2 13ºcos^2 47º+cos^2 73º =? …..................
trigonometry
0 Answer Available
Last Activity: 3 Years ago
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
0 Answer Available
Last Activity: 3 Years ago