Grade 11Trigonometry
Solve Cos x + Sin y = Cos 2x + Sin 2x [ x=2n pi x= 2n pi/3 + pi/6]
Solve Cos x + Sin y = Cos 2x + Sin 2x [ x=2n pi x= 2n pi/3 + pi/6]
1 Answer
Chirag jain
FIRSTLY IN PLACE OF SINY THERE WILL BE SINX
Cosx-cos2x=sin2x-sinx
2sin(3x/2)sin(x/2)=2sin(3x/2)cos(x/2)w
Sin3x{sin(x/2)-cos(x/2)}=0
Now,case1=}sin(3x/2)=sin0
3x/2=npi+(-1)^n×0
x=2npi/3_____1
Case2=} sin(x/2)=cos(x/2)
tan(x/2)=tan(pi/4)
x/2=npi+pi/4
x=2npi+pi/2 or,
x=2npi/3+pi/6
Thnx to give me a chance
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