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Grade: 11
        
Solve and write General solutions for equation   2sin2x+sin22x=2
 
one year ago

Answers : (1)

Aditya Gupta
1807 Points
							
It becomes sin^2 2x= 2cos^2 x
Now write sin2x as 2sinxcosx
2sin^2xcos^2x= cos^2x
cos^2xcos2x=0 coz cos2x= 1-2sin^2x
So cosx=0 or cos2x= 0
x = 2npi+- pi/2 or npi+-pi/4 n belonging to integer
one year ago
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