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Flag Trigonometry> SINA=nSINB THEN n-1/n+1 tan A+B/2=_______...
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SINA=nSINB THEN n-1/n+1 tan A+B/2=______________
A]SIN(A-B/2)
B] TAN (A-B/2)
C] COT (A-B/2)
D]NOT

KRISHA SHETH , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

we have sinA = k sinB.

implies k/1 = sinA /sinB.

applying dividendo and componendo ,we get
k-1/k+1=  sinA - sin B / sin A + sin B
=2 cos(A+B) / 2sin(A-B)/2 / 2  sin(A+B)  /  2 cos(A-B)/2

now finally we will have

tan(A-B)/2/ tan(A+B)/2  = k-1/k +1.


we obtain tan(A-B)/2
 
Option B is correct
 
 
Regards
Arun (askIITians forum expert)

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