sinA-cosA+1÷sinA+cosA-1= 1÷ secA - tanA, by using identity sec×secA=1+tan×tanA.
Prathamesh , 8 Years ago
Grade 10
Trigonometry> sinA-cosA+1÷sinA+cosA-1= 1÷ secA - tanA, ...
1 Answers
Arun
divide each term of the eqtn. by cosA
tanA-1+secA/tanA+1-secA
multiply this eqtn wth tanA-(1-sec A)/ tanA-(1-secA) and apply sec2A= tan2A+1!!
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