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Grade: 10 

                        
sinA-cosA+1÷sinA+cosA-1= 1÷ secA - tanA, by using identity sec×secA=1+tan×tanA.
3 years ago

Answers : (1)

Arun
24739 Points 
							
divide each term of the eqtn. by cosA 
tanA-1+secA/tanA+1-secA
multiply this eqtn wth tanA-(1-sec A)/ tanA-(1-secA) and apply sec2A= tan2A+1!!
3 years ago
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