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sinA-cosA+1÷sinA+cosA-1= 1÷ secA - tanA, by using identity sec×secA=1+tan×tanA.

sinA-cosA+1÷sinA+cosA-1= 1÷ secA - tanA, by using identity sec×secA=1+tan×tanA.

Grade:10

1 Answers

Arun
25763 Points
3 years ago

divide each term of the eqtn. by cosA 

tanA-1+secA/tanA+1-secA

multiply this eqtn wth tanA-(1-sec A)/ tanA-(1-secA) and apply sec2A= tan2A+1!!

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