(sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A) = ( sin3A)/sin5A .
(sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A) = ( sin3A)/sin5A .
Jayesh guptq , 4 Years ago
Grade 11
Trigonometry> (sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A) ...
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Rituraj Tiwari
Last Activity: 4 Years ago
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