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(sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A) = ( sin3A)/sin5A .

(sinA+2sin3A+sin5A)/(sin3A+2sin5A+sin7A) =  ( sin3A)/sin5A .

Grade:11

1 Answers

Rituraj Tiwari
askIITians Faculty 1792 Points
one year ago
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