sin4α+4cos4β+2=4√2sinacosb;α,β∈[0,π], then cos(α+β)−cos(α−β) is equal to :
sin4α+4cos4β+2=4√2sinacosb;α,β∈[0,π], then cos(α+β)−cos(α−β) is equal to :

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago