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sin3A÷1+2cos2A

sin3A÷1+2cos2A

Grade:9

3 Answers

Sharan
20 Points
6 years ago
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
Sharan
20 Points
6 years ago
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
PK NAIN
87 Points
5 years ago
 
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
 
 
 
 

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