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sin3A÷1+2cos2A

oshi , 10 Years ago
Grade 9
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Sharan

Last Activity: 10 Years ago

sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)

Sharan

Last Activity: 10 Years ago

sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)

PK NAIN

Last Activity: 9 Years ago

 
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
 
 
 
 

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