+91-87964 74404
FlagBACK
Question icon
Grade 9Trigonometry

sin3A÷1+2cos2A

Profile image of oshi
11 Years agoGrade 9
Answers icon

3 Answers

Profile image of Sharan
11 Years ago
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
Profile image of Sharan
11 Years ago
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
Profile image of PK NAIN
10 Years ago
 
sin3A           = 3sinA - 4sin3A            =    sinA(3 - 4sin2A)    =   sinA
1+2cos2A          1+2(1- 2sin2A)                 (3 - 4sin2A)
 
 
 
 

Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 3 Years ago

question mark
  • Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥 
trigonometry
1 Answer Available

Last Activity: 4 Years ago