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`        sin2x+sin4x+sin6x=0 find genral solution of this question by alternative method`
one month ago

Vikas TU
8732 Points
```							Dear student sin²A + cos²A = 1sin2A = 2sinAcosAsin3A = -4sin³A + 3sinAsin2x + sin4x + sin6x = 0 ==> siny + sin2y + sin3y = 0siny + 2siny cosy - 4sin³y + 3siny = 02siny cosy - 4sin³y + 4siny = 0siny cosy - 2sin³y + 2siny = 0siny (cosy - 2sin²y + 2) = 0siny (cosy - 2(1 - cos²y) + 2) = 0siny (cosy - 2 + 2cos²y + 2) = 0siny (cosy + 2cos²y) = 0siny cosy (1 + 2cosy) = 02siny cosy (2cosy + 1) = 0sin2y (2cosy + 1) = 0sin2y = 0 OR cosy = -1/2sin4x = 0 OR cos2x = -1/2x = 0, π/4, π/3, π/2, 2π/3, 3π/4, π, 5π/4, 4π/3, 3π/2, 7π/4, 5π/3   ANSWER
```
one month ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
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