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Sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

Sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)
 
 

Grade:11

1 Answers

Vikas TU
14149 Points
3 years ago

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