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(sin theta-cos theta/sin theta+cos theta)+(sin theta+cos theta/sin theta-cos theta)=2/sin^2 theta-1

(sin theta-cos theta/sin theta+cos theta)+(sin theta+cos theta/sin theta-cos theta)=2/sin^2 theta-1

Grade:10

1 Answers

Shashank Singh
askIITians Faculty 57 Points
6 years ago
(sin theta – cos theta)^2 + (sin theta + cos theta)^2/ (sin^2theta-cos^2theta)
= 2(sin^2theta+cos^2theta)/2sin^2theta-1
= 2/(2sin^2theta-1)........... [ans]

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