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Grade 12th passTrigonometry

sin​​​​×+cos*=1

Profile image of himanshu
11 Years agoGrade 12th pass
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1 Answer

Profile image of Jitender Singh
11 Years ago
Ans:Hello student, please find answer to your question
Please rewrite the complete question.
Properly write the all the functions.
Complete the equation.
Also, define the interval in which you want the results.

sin(x) + cos(x) = 1
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
sin(x+\frac{\pi }{4}) = sin(x)cos(\frac{\pi }{4}) + cos(x)sin(\frac{\pi }{4})
sin(x+\frac{\pi }{4}) = \frac{sin(x) + cos(x)}{\sqrt{2}}
sin(x) + cos(x)=\sqrt{2}sin(x+\frac{\pi }{4})
\sqrt{2}sin(x+\frac{\pi }{4}) = 1
sin(x+\frac{\pi }{4}) = \frac{1}{\sqrt{2}}
x+\frac{\pi }{4} = 2n\pi + \frac{\pi }{4}
x = 2n\pi
x = 0, 2\pi