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sin(B+A)+cos(B-A)/sin(B-A)+cos(B+A) If cosA + cosB=0=sinA + sinB,then cos2A +cos2B=

  1.  sin(B+A)+cos(B-A)/sin(B-A)+cos(B+A)
  2. If cosA + cosB=0=sinA + sinB,then cos2A +cos2B=

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
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