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Divide by 2 both side
sinA / 2 + sinB / 2 = root(3).cosA/2 - root(3).cosB/2
1/2 . sinA - root(3)/2 .cosA = - root(3)/2 . cos(B) - 1/2 . sin(B)
sin(A - 60) = - sin(B + 60)
so finaly A -60= - 60 - B
so A = -B
Therefore, Sin3B + sin3A = 0
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