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`        Sin A = 336/ 625 where 450 degree  `
2 years ago

```							If 450° So A is in the second quadrant. so cos A = -√(1 - (336/625)²) = -527/625 I like tan(x/2) = (1 - cos(x))/sin(x) because it has no radicals in it. tan(A/2) = (1 + 527/625)/(336/625) = 24/7 If 450° A reference triangle for A/2 would then be y = -24, x = -7, r = 25 So cos(A/2) = -7/25 and sin(A/2) = -24/25 Then tan(A/4) = (1 - cos(A/2))/sin(A/2) = (1 + 7/25)/(-24/25) = -4/3 If 450° A reference triangle for A/2 would then be y = 4, x = -3, r = 5 So sin(A/4) = 4/5 CHECK We note that arcsin(336/625) = 0.5675882184 radians = 32.52040941662392° which is in the first quadrant. Subtract it from 180° and we get 147.47959058337608 which is in the second quadrant. Add 360° and we get A = 507.4795905833761° So sin(A/4) comes out 0.8 = 4/5
```
4 months ago
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