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Grade: 11
        
Sin A = 336/ 625 where 450 degree
 
2 years ago

Answers : (1)

Shankar
20 Points
							
If 450°
So A is in the second quadrant. 
so cos A = -√(1 - (336/625)²) = -527/625 

I like tan(x/2) = (1 - cos(x))/sin(x) because it has no radicals in it. 

tan(A/2) = (1 + 527/625)/(336/625) = 24/7 

If 450°

A reference triangle for A/2 would then be y = -24, x = -7, r = 25 

So cos(A/2) = -7/25 and sin(A/2) = -24/25 

Then tan(A/4) = (1 - cos(A/2))/sin(A/2) = (1 + 7/25)/(-24/25) = -4/3 

If 450°

A reference triangle for A/2 would then be y = 4, x = -3, r = 5 

So sin(A/4) = 4/5 

CHECK 
We note that arcsin(336/625) = 0.5675882184 radians = 32.52040941662392° 
which is in the first quadrant. 
Subtract it from 180° and we get 147.47959058337608 
which is in the second quadrant. 
Add 360° and we get A = 507.4795905833761° 

So sin(A/4) comes out 0.8 = 4/5
4 months ago
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