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Sin^8x - cos^8x = (sin^2x - cos^2x)×(1-2sin^2x cos^2x)

Sin^8x - cos^8x = (sin^2x - cos^2x)×(1-2sin^2x cos^2x)
 

Grade:11

1 Answers

Anish Singhal
askIITians Faculty 1192 Points
5 years ago
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