Grade 12th passTrigonometry
(sin 8x+ 7 sin 6x + 18 sin 4x+ 12 sin 2x)/(sin 7x + 6 sin 5x+12 sin 3x)=
(sin 8x+ 7 sin 6x + 18 sin 4x+ 12 sin 2x)/(sin 7x + 6 sin 5x+12 sin 3x)=
1 Answer
Aditya Gupta
hello vrinda, this is an easy ques. lets understand how to solve it.
write numerator N= sin 8x+ 7 sin 6x + 18 sin 4x+ 12 sin 2x as (sin 8x+sin 6x) + 12(sin 4x+sin 2x) + 6(sin6x+sin4x). now we use the formula sinx+siny= 2sin(x+y)/2cos(x – y)/2
so N= 2sin7xcosx + 24sin3xcosx + 12sin5xcosx= 2cosx(sin 7x + 6 sin 5x+12 sin 3x)
or (sin 8x+ 7 sin 6x + 18 sin 4x+ 12 sin 2x)/(sin 7x + 6 sin 5x+12 sin 3x)= 2cosx
kindly approve :)
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