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Sin(4a-2b)+sin(4b-2a)/cos(4a-2b)+cos(4b-2a)=tan(a+b).plzz help me to prove this identity

Sin(4a-2b)+sin(4b-2a)/cos(4a-2b)+cos(4b-2a)=tan(a+b).plzz help me to prove this identity

Grade:11

1 Answers

N Hemavathi
17 Points
7 years ago
= (2sin(4a-2b+4b-2a)/2 cos(4a-2b-4b+2a)/2 ) / (2cos(4a-2b+4b-2a)/2 cos(4a-2b-4b+2a)/2 )
 
=sin(a+b) / cos(a+b)
 
= tan(a+b)
 
hence proved

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