(sin θ - 2sin3θ)/(2cos3θ-cos θ) = tan θ prove the following
(sin θ - 2sin3θ)/(2cos3θ-cos θ) = tan θ
prove the following
Pawan Prajapati , 5 Years ago
Grade 12
Trigonometry> (sin θ - 2sin3θ)/(2cos3θ-cos θ) = tan θ p...
1 AnswersVikas TU
Dear student
(sin θ - 2sin3θ)/(2cos3θ-cos θ) = tan θ
L.H.S. = (sin θ - 2sin3θ)/(2cos3θ - cos θ)
= [sin θ(1 - 2sin2θ)]/[cos θ(2cos2θ- 1)]
= sin θ[1 - 2(1-cos2θ)]/[cos θ(2cos2θ -1)]
= [sin θ(2cos2θ -1)]/[cos θ(2cos2θ -1)]
= tan θ = R.H.S.
L.H.S. = (sin θ - 2sin3θ)/(2cos3θ - cos θ)
= [sin θ(1 - 2sin2θ)]/[cos θ(2cos2θ- 1)]
= sin θ[1 - 2(1-cos2θ)]/[cos θ(2cos2θ -1)]
= [sin θ(2cos2θ -1)]/[cos θ(2cos2θ -1)]
= tan θ = R.H.S.
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