#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Ajay
209 Points
4 years ago
Hi Riya
You can use the formula for Sum and Difference for Sin to get the required solution. Have  look below and hope you understand the derivation
${ sin }^{ 2 }A-{ sin }^{ 2 }B\quad =\quad (sinA+sinB)(sinA-sinB)\\ Using\quad formula\quad for\quad sum\quad and\quad difference\quad for\quad sin\\ =\quad \left( 2cos\frac { (A+B) }{ 2 } sin\frac { (A-B) }{ 2 } \right) \left( 2sin\frac { (A+B) }{ 2 } cos\frac { (A-B) }{ 2 } \right) \\ Rearranging\quad \\ =\quad \left( 2sin\frac { (A+B) }{ 2 } cos\frac { (A+B) }{ 2 } \right) \left( 2sin\frac { (A-B) }{ 2 } cos\frac { (A-B) }{ 2 } \right) \\ We\quad know\quad \quad 2sinxcosx\quad =\quad sin2x\\ =sin(A+B)sin(A-B)$

riya
10 Points
4 years ago
Thank you .I got it now. I was not equating the second last LHS to sin2x but now I got it thanks a lot .I need to concentrate more.