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sin2a/2+sin2b/2+sin2c/2=1-2sina/2*sinb/2*sinc/2

CHIKUN GARTIA , 9 Years ago
Grade 11
anser 1 Answers
Vijay Mukati

Last Activity: 9 Years ago

Hint: Take RHS: 1+sinc/2 (-2sina/2 sinb/2) tehn convert into 1+sinc/2(cos(a+b)/2 – cos(a-b)/2), then convert into 1+sinc/2 (sinc/2 – cos(a-b/2)) then final simplify to get 1 – cos2a/2 + sin2b/2 + sin2c/2. Thanks.

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