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sin 2 a/2+sin 2 b/2+sin 2 c/2=1-2sina/2*sinb/2*sinc/2

sin2a/2+sin2b/2+sin2c/2=1-2sina/2*sinb/2*sinc/2
 

Grade:11

1 Answers

Vijay Mukati
askIITians Faculty 2590 Points
8 years ago
Hint: Take RHS: 1+sinc/2 (-2sina/2 sinb/2) tehn convert into 1+sinc/2(cos(a+b)/2 – cos(a-b)/2), then convert into 1+sinc/2 (sinc/2 – cos(a-b/2)) then final simplify to get 1 – cos2a/2 + sin2b/2 + sin2c/2. Thanks.

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