0

Guest

Courses New

sin^2 6°-sin^2 12°+sin^2 18°-sin^2 24°......15 solve it

sin^2 6°-sin^2 12°+sin^2 18°-sin^2 24°......15 solve it

Question Image
Grade:12th pass

1 Answers

Akhand
23 Points
6 years ago
(1-cos2x6)/2 +(1-cos24)/2+ …......................+(1-cos180)/2
15/2 -1/2(cos12 +cos24...........+cos180) use cos(a)+cos (a+b) +cos(a+2b)+....(cos(a+nb)=
{sin(nb/2)cos[a+(n-1)b/2]}/sinb/2
sin90xcos96/sin6=-1

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More