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```
sin^2 6°-sin^2 12°+sin^2 18°-sin^2 24°......15 solve it

```
4 years ago

Akhand
23 Points
```							(1-cos2x6)/2 +(1-cos24)/2+ …......................+(1-cos180)/215/2 -1/2(cos12 +cos24...........+cos180) use cos(a)+cos (a+b) +cos(a+2b)+....(cos(a+nb)={sin(nb/2)cos[a+(n-1)b/2]}/sinb/2sin90xcos96/sin6=-1
```
4 years ago
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### Course Features

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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions