sin^(-1) (x^2-2x+1) + cos^(-1) (x^2 -x) =π/2 Solve the equation
sin^(-1) (x^2-2x+1) + cos^(-1) (x^2 -x) =π/2
Solve the equation
Prathu , 7 Years ago
Grade 12th pass
Trigonometry> sin^(-1) (x^2-2x+1) + cos^(-1) (x^2 -x) =...
1 Answers
Aditya Gupta
Last Activity: 7 Years ago
we know that sin-1y+cos-1y=π/2 is an identity.
so the equation then becomes
x=1sin^(-1) (x^2-2x+1) = π/2 – cos^(-1) (x^2 -x) =sin-1(x^2 -x)taking sin both the sides, we get x^2-2x+1=x^2-x; or
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