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Sin^-1(1/3)+sin^-1(2/3)=sin(√a+√b/c),then find values of [b/a]

Sin^-1(1/3)+sin^-1(2/3)=sin(√a+√b/c),then find values of [b/a]

Grade:10

2 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
Dear student

Please write the Question in a standard form or attach an image of the question

Regards
Vikas TU
14149 Points
3 years ago
Dear student 
Question is not clear 
Please attach an image, 
We will happy to  help you 
Good Luck
Cheers
 

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