0

Guest

Courses New

(Sectheta+tantheta-1/tantheta-sectheta+1)whole square

(Sectheta+tantheta-1/tantheta-sectheta+1)whole square
 

Grade:12th pass

1 Answers

Prakhar
13 Points
5 years ago
(tan a + sec a -1)^2/(tan a- sec a + 1)^2
=(tan^2 a + sec^2 a + 2tan a*sec a-2sec a -2tan a)/(tan^2 a + sec^2 a +1 - 2tan a*sec a -2sec a + 2 tan a)
=(2sec ^2 a + 2 tan a * sec a -2sec a- 2tan a)/(2sec^2 a - 2tan a* sec a - 2sec a + 2tan a)
={2sec a(sec a -1) + 2tan a(sec a-1)}/{2sec a(sec a-1) - 2tan a (sec a-1)}
=(2sec a + 2tan a)(sec-1)/(2sec a -2tan a)(sec a-1)
=(sec a + tan a)/(sec a - tan a) *(sec a+ tan a)/(sec a + tan a)
=sec^2 + tan^2 + 2tan a*sec a
=2tan^2+ 1+2tan a*sec a
=2tan a(tan a + sec a) +1
=
 

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More