Grade 11Trigonometry
SecA-tanA/secA pulse tanA equal to 1-2secAtanA pulse 2tans squareA
1 Answer
Nishant Vora
use the fact that sec^2 – tan^2 = 1
hence, (secA + tanA)(secA - tanA) = 1
=>(secA + tanA) = 1/(secA - tanA)
hence, (secA + tanA)(secA - tanA) = 1
=>(secA + tanA) = 1/(secA - tanA)
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