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question : find general solution for given equation: sin 3x + cos 2x = 0 .

ankur , 8 Years ago
Grade 12
anser 1 Answers
Arun
Dear Ankur
 
cos 2x = - sin 3x
 
cos 2x = cos (\pi/2 + 3x)
 
Now
 
2x = 2n\pi ± (\pi/2 + 3x)
 
Taking +ve sign
 
2x = 2n\pi + \pi/2 + 3x
 
x = -(2n\pi + \pi/2)
 
 
Now taking -ve sign
 
2x = 2n\pi - \pi/2 - 3x
 
x = (1/5)(2n\pi - \pi/2)
 
 
 
Regards
Arun (askIITians forum expert)
Last Activity: 8 Years ago
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