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Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

Grade:12th pass

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
3^(sinx + cosy) = 1
 
Hence sinx + cos y = 0
sinx = - cosy
 
Now
 
25^(cos²y + cos²y) = 5
 
2cos²y = ½
 
Cos²y = ¼
 
Cos²y = cos² pi/3
 
y = 2n*pi ± pi/3

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