Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

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Arun · Answer

Dear student 3^(sinx + cosy) = 1 Hence sinx + cos y = 0 sinx = - cosy Now 25^(cos²y + cos²y) = 5 2cos²y = ½ Cos²y = ¼ Cos²y = cos² pi/3 y = 2n*pi ± pi/3

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Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

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Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

Q1) solve: 3^(sinx +cosy)=1 and 25^{(sinx)^2 + (cosy)^2}=5

1 Answers

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Other Related Questions on Trigonometry

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