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prove that tan 15 – cot 75 = sec15 / sec square 15 – 1 .

prove that tan 15 – cot 75 = sec15 / sec square 15 – 1 .

Grade:10

1 Answers

Arun
25750 Points
6 years ago
This question is wrong.
Because 
As we know
Cot75 = cot(90- 15) = tan15
Hence LHS = 
tan15 - tan15 = 0
But RHS is not zero
 
 

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