Prove that sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

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Prove that sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

Prove that sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

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Prove that sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

Prove that sin2A+sin2B+sin2C-sin2(A+B+C)=4sin(B+C).sin(C+A).sin(A+B)

1 Answers

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Other Related Questions on Trigonometry

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