Last Activity: 4 Years ago
Welcome to AskIITiansLHS=(sec 8θ -1 )/ (sec4θ -1)=(1/(cos8θ) -1 )/ (1/(cos4θ) -1)=((1-cos8θ)cos4θ )/ ((1-cos4θ) cos8θ)=(2sin24θcos4θ )/ ((2sin22θ) cos8θ)=(2sin4θcos4θsin4θ )/ ((2sin22θ) cos8θ)=(sin8θ * 2sin2θcos2θ )/ ((2sin22θ) cos8θ)=(tan8θ * cos2θ )/ (sin2θ)= (tan8θ) /(tan 2θ)= RHSHence proved.Thanks
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Last Activity: 2 Year ago(s)