Soumendu Majumdar
Last Activity: 7 Years ago
Dear Student,
First to make the problem easier square both sides L.H.S & R.H.S
so we need to prove (sec A – tan A)^2 = ( 1 + sin A)/( 1 – sin A)
Now L.H.S= { (1 – sin A)/(cos A)}^2
= { (1- sin A)^2}/(1- sin^2 A) = {(1- sin A)^2}/(1 + sin A)(1- sin A)
= ( 1 – sin A)/(1 + sin A) = R.H.S [Proved]
Hope it helps!