+91-87964 74404
FlagBACK
Question icon
Grade 10Trigonometry

  1. prove that sec^2thia = cos^2thita can never be less than 2
  2. xcothita-ysinthita=a xsinthita+ycosthita=b then prove that x^2+y^2=a^2+b^2

Profile image of Amogh
11 Years agoGrade 10
Answers icon

1 Answer

Profile image of Y RAJYALAKSHMI
11 Years ago
I think you need to check these  problems.  
1.check the sign for sec^2thia = cos^2thita ( may not be =)
2. The second problem should be xcos thita – ysinthita = a & xsin thita + ycos thita = b.  Then square these equations and add.
 
 
Pl. check
 

Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 3 Years ago

question mark
  • Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥 
trigonometry
1 Answer Available

Last Activity: 4 Years ago