Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
Please find the solution to your problem.
Consider b-c/b+c
= 2RsinB – 2RsinC/2RsinB + 2RsinC
= 2R(sinB – sinC)/(sinB + sinC)
= 2cos(B + C/2) × sin(B – C/2)/2sin(B + C/2) × cos(B – C/2) = cot(B + C/2) × tan(B – C/2)
= cot(90° – A/2) × tan(B – C/2)
= tanA/2 × tan(B – C/2)
Hence, tan(B – C/2) = b-c/b+c × cot(A/2)
Thanks and regards,
Kushagra