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Trigonometry

prove that in a triangle ABC summation(sinAsin(B-C))=0

Profile image of Rishu
10 Years agoGrade
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2 Answers

Profile image of Karthik Pasupulatei
10 Years ago
first write sin2A then 2SINA.COSA then write 2SINA.COS(90-B-C) THEN U WRITE 2SINA SIN(B-C)
Profile image of Lab Bhattacharjee
10 Years ago
B+C=\pi-A\implies\sin(B+C)=\cdots=\sin A \\ \sin A\cdot\sin(B-C)=\sin(B+C)\sin(B-C)=\sin^2B-\sin^2C

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