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Grade: 11

                        

Prove that cos6x = 32cos^6x - 48cos^4x + 18cos^2x – 1

3 years ago

Answers : (1)

Arun
24742 Points
							
cos6x=cos[2(3x)]=2cos2(3x)-1 cos2x=2cos2x-1 =2[cos(3x)]2-1 cos3x=4cos3x-3cosx =2[4cos3x-3cosx]2-1 (a-b)2=a2+b2-2ab =2[16cos6x+9cos2x-24cos4x]-1 =32cos6x-48cos4x+18cos2x-1
3 years ago
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