Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Prove that ~16cos24°.cos48°.cos96°.cos168° =1This question is from S.L.Loney Plane trigonometry part -I

Prove that ~16cos24°.cos48°.cos96°.cos168° =1This question is from S.L.Loney Plane trigonometry part -I

Grade:11

3 Answers

Deepak Kumar Shringi
askIITians Faculty 4405 Points
3 years ago
562-2116_Capture.PNG
Siddharth Singh
100 Points
3 years ago
the dipole moment p induced in an atom of neon gas whe an electric field E is applied. , isP = \alpha\varepsilono E P = np = \varepsilono(K –1)E p = \varepsilono (K –1)E / N the volume of 1 m atoms of neon at N.T.P. is 22.4 litres. N = Na / V Hence on calculation p = 2.65 * 10 ^ –36 Cm
Soumendu Majumdar
159 Points
3 years ago
Dear Student,
L.H.S = 4(2cos24^\circ cos96^\circ)(2cos48^{\circ}cos168^{\circ})
4(cos120^{\circ}+cos72^{\circ})(cos216^{\circ}+cos120^{\circ})
4(-sin30^{\circ}+sin18^{\circ})(-cos36^{\circ}-sin30^{\circ})
Now,
sin 18^{\circ}= (\sqrt5 -1)/4
cos 36^{\circ}= (\sqrt5 +1)/4
so L.H.S = 
4(\sqrt5-3)(-3-\sqrt5)/16
(9-5)/4
1 =R.H.S [Proved]
Hope it helps!
with regards,
Soumendu
P.S-If you have any confusion in understanding the solution, feel free to ask, I’ll be glad to help you!

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free