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Grade 10Trigonometry

PROVE THAT (1+tanAtanB)2+(tanA-tanB)2=sec2A×sec2B

Profile image of saivarun
10 Years agoGrade 10
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1 Answer

Profile image of Aakanksha Talreja
10 Years ago
Expand it n factorise it u will get d result
1+\tan ^{2}A*\tan ^{2}B+2\tan A\tan B+\tan ^{2}A+\tan ^{2}B-2\tan A\tan B=1+\tan ^{2}A+\tan ^{2}A*\tan ^{2}B+\tan ^{2}B=(1+\tan ^{2}A)(1+\tan ^{2}B)=\sec ^{2}A\sec ^{2}B

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