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Grade: 11

                        

prove cos 6 x = 1/32(cos 6x + 6 Cos 4x + 15 Cos 2x + 10)

3 years ago

Answers : (1)

Arun
24742 Points
							
I have solved it with a simple and smart approach.
 
cos^6x=((e^ix+e^-ix)/2)^6 
=1/2^6(e^6ix+6e^5ixe^-ix+15e^4ixe^-2ix 
+20e^3ixe^-3ix+15e^2ixe^-4ix 
+6e^ixe^-5ix+e^-6ix) 
=1/32(((e^6ix+e^-6ix)/2) 
+6((e^4ix+e^-4ix)/2) 
+15((e^2ix+e^-2ix)/2) 
+10) 
cos^6x=1/32(15cos2x 
+6cos4x 
+cos6x 
+10)
3 years ago
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