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plz help me to solv this. if A+B+C=pie ,cosA=cosBcosC , prove that tanA=tanB+tanC

sudipta biswas , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

R.H.S.
= tanB+tanC
= (sinB/cosB)+(sinC/cosC)
= (sinBcosC+cosBsinC)/(cosB.cosC)     
= sin(B+C)/cosA            [cosA=cosB.cosC]
= sinA/cosA                    [A+B+C=pie, B+C=pie-A, sin(B+C)=sin(pie-A)= sinA]
= tanA = L.H.S. Proved

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