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         Please Solve this ques with proper reasons....?.........................
one year ago

2020 Points
							the above question has been taken from tmh jee advanced. it is a tricky question and its hard to understand the solution as well. lemme help u out tho, so u can get the reason as well.Jensens Inequality: Suppose $h(x)$ is a twice differentiable, real-valued function on an interval $[a,b]$ and that $h^{}(x)>0$ for all $a. Then, for every positive integer m and for all points $x_{1}, x_{2}, \ldots x_{m}$ in $[a,b]$, we have$h(\frac{x_{1}+x_{2}+\ldots+x_{m}}{m}) \leq \frac{h(x_{1})+h(x_{2})+h(x_{3})+\ldots+h(x_{m})}{m}$Moreover, equality holds if and only if $x_{1}=x_{2}=\ldots=x_{m}$. A similar result holds if$h^{}(x)<0$ for all $a except that the inequality sign is reversed.now, if we set h(x)=sinx, h’(x)=cosx or h”(x)= – sinx. it is given in question that x1, x2, …..xn lie in the interval (0,π). in ths interval, sinx is positive, implying h”(x)so, h((x1+x2+...xn)/n)=sin(π/n) >= (sinx1+sinx2+....sinxn)/nso, the greatest value of the sum turns out to be n*sin(π/n), which occurs when all xi’s are equal to each other.

one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions