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Please provide solution to above question. Image attached

Vineet Tanna , 10 Years ago
Grade 12th pass
anser 1 Answers
BALAJI ANDALAMALA
\sqrt{2+\sqrt{2-\sqrt{2(1+cos\theta)}}} = \sqrt{2+\sqrt{2-\sqrt{2(2cos^2\frac{\theta}{2})}}}
= \sqrt{2+\sqrt{2-2cos\frac{\theta}{2})}} = \sqrt{2+\sqrt{2(1-cos\frac{\theta}{2})}}
= \sqrt{2+\sqrt{4sin^2\frac{\theta}{4})}}
= \sqrt{2+2sin\frac{\theta}{4}}=\sqrt{2}(sin\frac{\theta}{8}+cos\frac{\theta}{8})
= 2cos(\frac{\pi}{4}-\frac{\theta}{8})
Last Activity: 10 Years ago
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