0

Guest

Courses New

Please provide solution to above question. Image attached

Please provide solution to above question. Image attached

Question Image
Grade:12th pass

1 Answers

BALAJI ANDALAMALA
askIITians Faculty 78 Points
8 years ago
\sqrt{2+\sqrt{2-\sqrt{2(1+cos\theta)}}} = \sqrt{2+\sqrt{2-\sqrt{2(2cos^2\frac{\theta}{2})}}}
= \sqrt{2+\sqrt{2-2cos\frac{\theta}{2})}} = \sqrt{2+\sqrt{2(1-cos\frac{\theta}{2})}}
= \sqrt{2+\sqrt{4sin^2\frac{\theta}{4})}}
= \sqrt{2+2sin\frac{\theta}{4}}=\sqrt{2}(sin\frac{\theta}{8}+cos\frac{\theta}{8})
= 2cos(\frac{\pi}{4}-\frac{\theta}{8})

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More