Last Activity: 8 Years ago
-> tan(π/4 + x) / tan(π/4 - x)....Expanding using identities....Tan(x+y) = (tan x + tan y) / (1 - tan x tan y)...and...Tan(x-y) = (tan x - tan y) / (1 + tan x tan y)....tanπ/4=1.... -> [ (1+tan x)/(1-tanx) ] / [ (1-tanx)/(1+tanx) ] -> [ (1+tanx)² / (1-tanx)² ]... -> [ 1+tanx / 1-tanx ]²....Hence proved
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Last Activity: 2 Year ago(s)