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`        Please help me in solving above attached image question to proof`
one year ago

1819 Points
```							simply take sin on both sides and multiply by ab, to getc^2= xroot(b^2-y^2)+yroot(a^2-x^2)square both sides and rearrange to getc^4-x^2b^2-a^2y^2= 2xy[ root{(b^2-y^2)(a^2-x^2)} – xy]....(1)now, a^2b^2 – c^4= a^2b^2 – x^2b^2 – y^2a^2– 2xy[ root{(b^2-y^2)(a^2-x^2)} – xy]taking root both sides we getroot(a^2b^2 – c^4)= – xy + root(b^2-y^2)(a^2-x^2)......(2)from (1) nd (2), we havec^4=x^2b^2+a^2y^2+2xyroot(a^2b^2 – c^4)
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions