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question mark

PLEASE GIVE ME THE ANSWER.

SHANMUKESHWAR , 10 Years ago
Grade 11
anser 11 Answers
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9.42
Last Activity: 10 Years ago
PRAPULPODISHETTI
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
 
 
ApprovedApproved
Last Activity: 10 Years ago
RAKESH CHINDAM
WHAT IS U R QUASTION
Last Activity: 10 Years ago
sanjay
 
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
Last Activity: 10 Years ago
RAKESH CHINDAM
 
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
Last Activity: 10 Years ago
Gavvala Ganesh
 
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
Last Activity: 10 Years ago
Akhil Chinnu
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3
Last Activity: 10 Years ago
L GOUSE BASHA
AREA OF SECTOR FORMULA IS A = πr2  
RADIUS OF CIRCLE IS 6cm
CENTRAL ANGLE IS 300
AREA OF SECTOR IS A= π(6)2=36π
Last Activity: 10 Years ago
Raghu Vamshi Hemadri
 
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
 
Last Activity: 10 Years ago
R.GANGARAJU
 
Radius of circle r=6cm,
central angleθ=30deg..
Area of the sector =1/2r2 θ
                           S=(1/2)(62)(30)(π/180)
                           S=3π cm3.
Last Activity: 10 Years ago
SAI SARDAR
Shanmukeswar, The answer is 9.42.It is from the substitution of radius and angle in the formula of 1/2r2 (angle).
 
Last Activity: 10 Years ago
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