## Guest

11 Points
9 years ago
9.42
PRAPULPODISHETTI
669 Points
9 years ago
central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.

RAKESH CHINDAM
428 Points
9 years ago
WHAT IS U R QUASTION
sanjay
206 Points
9 years ago

central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.
RAKESH CHINDAM
428 Points
9 years ago

central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.
Gavvala Ganesh
551 Points
9 years ago

central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.
Akhil Chinnu
45 Points
9 years ago
central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3
L GOUSE BASHA
316 Points
9 years ago
AREA OF SECTOR FORMULA IS A = πr2
CENTRAL ANGLE IS 300
AREA OF SECTOR IS A= π(6)2=36π
72 Points
9 years ago

central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.

R.GANGARAJU
68 Points
9 years ago

central angleθ=30deg..
Area of the sector =1/2r2 θ
S=(1/2)(62)(30)(π/180)
S=3π cm3.
SAI SARDAR
1700 Points
8 years ago
Shanmukeswar, The answer is 9.42.It is from the substitution of radius and angle in the formula of 1/2r2 (angle).