PRAPULPODISHETTIApproved Tutor Answer11 Years agoRadius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
sanjay11 Years ago Radius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
RAKESH CHINDAM11 Years ago Radius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
Gavvala Ganesh11 Years ago Radius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
Akhil Chinnu10 Years agoRadius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3
L GOUSE BASHA10 Years agoAREA OF SECTOR FORMULA IS A = πr2 RADIUS OF CIRCLE IS 6cm CENTRAL ANGLE IS 300 AREA OF SECTOR IS A= π(6)2=36π
Raghu Vamshi Hemadri10 Years ago Radius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
R.GANGARAJU10 Years ago Radius of circle r=6cm,central angleθ=30deg..Area of the sector =1/2r2 θ S=(1/2)(62)(30)(π/180) S=3π cm3.
SAI SARDAR10 Years agoShanmukeswar, The answer is 9.42.It is from the substitution of radius and angle in the formula of 1/2r2 (angle).