Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
Please give me a step wise solution of question with each & every reason Please give me a step wise solution of question with each & every reason
From 2nd eq in question...-> ax sinß / cos²ß = by cosß / sin²ß…-> tan³ß = by / ax-> tanß = (by/ax)⅓...From tanß you can take out sinß and cos ß which are respectively:::: sinß = (by)⅓ / sqroot of [ (by)⅔ + (ax)⅔ ]…cosß = (ax)⅓ / sqroot of [ (by)⅔ + (ax)⅔ ]…Putting this in 1st eq in the question....-> [ ax/ (ax)⅓ + by/ (by)⅓ ]*[sqroot of [ (by)⅔ + (ax)⅔ ] ] = a² - b².....-> [ (by)⅔ + (ax)⅔ ]⅔ = a² - b²....-> (by)⅔ + (ax)⅔ = ( a² - b ) ^ 3/2....Hence proved...
Correction for the last step::-> [ (by)⅔ + (ax)⅔ ] ^3/2( instead of 2/3 wrongly printed ) = a² - b²....-> (by)⅔ + (ax)⅔ = ( a² - b ) ^ 2/3......Hence proved...Sorry the powers were wrongly wriiten by me because of a little confusion but rest of the solution just before the last step remain s the same..
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -