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Grade: 11

                        

Please give me a step wise solution of question with each & every reason

4 years ago

Answers : (2)

Faiz
107 Points
							From 2nd eq in question...-> ax sinß / cos²ß = by cosß / sin²ß…-> tan³ß = by / ax-> tanß = (by/ax)⅓...From tanß you can take out sinß  and cos ß which are respectively:::: sinß = (by)⅓ / sqroot of [ (by)⅔ + (ax)⅔ ]…cosß = (ax)⅓ / sqroot of [ (by)⅔ + (ax)⅔ ]…Putting this in 1st eq in the question....-> [ ax/ (ax)⅓ + by/ (by)⅓ ]*[sqroot of [ (by)⅔ + (ax)⅔ ] ] = a² - b².....-> [ (by)⅔ + (ax)⅔ ]⅔ = a² - b²....-> (by)⅔ + (ax)⅔ = ( a² - b ) ^ 3/2....Hence proved...
						
4 years ago
Faiz
107 Points
							Correction for the last step::-> [ (by)⅔ + (ax)⅔ ] ^3/2( instead of 2/3 wrongly printed ) = a² - b²....-> (by)⅔ + (ax)⅔ = ( a² - b ) ^ 2/3......Hence proved...Sorry the powers were wrongly wriiten by me because of a little confusion but rest of the solution just before the last step remain s the same..
						
4 years ago
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