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Grade: 11
        
please find the least value  of cos^2-6sinacosa+2+3sin^2a
 
2 months ago

Answers : (2)

Vikas TU
9468 Points
							
Dear student 
Cos^2Q - 6SinQ*CosQ + 3Sin^2Q + 2
Cos^2Q + Sin^2Q +1 - Cos2Q -3Sin2Q 
=> 1+1 - Cos2Q -3Sin2Q +2 
=> 4 - [Cos2Q-3sin2Q]
Minimum value 
=> 4 - sqrt((-1)^2 + (-3)^2 )
=> 4- sqrt(10)
Hope this helps 
 
2 months ago
Arun
22984 Points
							
 
maximum value is 3
cos^2a-6sinacosa +2+3sin^2a=cos^2a +sin^2a +2sin^2a -6sina cosa=3 +2sin2a(sin2a-3)
it will have maximum value when second term is maximum value at sin2a minimum is -1
therefore 3+2*-1(-1-3)=11
2 months ago
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