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Please answer the question no 93 if your answer is correct then I will approve you

Chandan Kumar , 7 Years ago
Grade 11
anser 1 Answers
NIKHIL GHODKE
SecXcos5X+1=0 or,
secXcos5X=-1 ,
cos5X=-1/secX 
cos5X=-cosX 
 cos5X+cosX=0 
2cos(5X+X)/2cos(5X-X)/2=0 
cos3Xcos2X=0
 (4cos³X-3cosX)(2cos²X-1)=0
. Either, 4cos³X-3cosX=0
4cos³X=3cosX or, cos²X=3/4 or, cosX= +  – √3/2 (has 4 solution in 0 to 360 deg)
also cos²X=1/2  (has 4 solution in 0 to 360 deg).
now i think i should get ur approval 
simple right
 
 
ENJOY LEARNING
 
 
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Last Activity: 7 Years ago
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