Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Please answer the question as soon as possible thanks

Please answer the question as soon as possible thanks

Question Image
Grade:11

1 Answers

Avinash
52 Points
3 years ago
Let 2tan `√[a-b/a+b].tan∆/2=xTan x/2=√a-b/a+b.tan∆/2 We know that;Cos x=1-tan^ x/2/1+tan^ x/2Now substitute tan x value in above equation;Cos x=1-(a-b /a+b )tan^∆/2//1+(a-b /a+b ).tan^x/2Now take Lcm.a+b-(a-b)tan^∆/2//a+b+ (a-b) tan^∆/2now substitute tan^∆/2=sin^∆/2//cos^∆/2a(cos^∆/2-sin^∆/2) +b(cos^∆/2+sin^∆/2)//a(cos^∆/2+sin∆/2)+b(cos^∆/2-sin^∆/2)We know that cos^∆/2-sin^∆/2=cos∆and cos^∆/2+sin^∆/2=1Therefore cos x=acos∆+b//a+bcos∆;X=cos`[acos∆+b//a+bcos∆]So option.A

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free